(2x+1)^(2)-(4x+3)*(x-2)=2-3x

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Solution for (2x+1)^(2)-(4x+3)*(x-2)=2-3x equation: 



(2x+1)^(2)-(4x+3)(x-2)=2-3x

We move all terms to the left:

(2x+1)^(2)-(4x+3)(x-2)-(2-3x)=0

We add all the numbers together, and all the variables

(2x+1)^2-(4x+3)(x-2)-(-3x+2)=0

We get rid of parentheses

(2x+1)^2-(4x+3)(x-2)+3x-2=0

We multiply parentheses ..

-(+4x^2-8x+3x-6)+(2x+1)^2+3x-2=0

We add all the numbers together, and all the variables

-(+4x^2-8x+3x-6)+3x+(2x+1)^2-2=0

We get rid of parentheses

-4x^2+8x-3x+3x+(2x+1)^2+6-2=0

We add all the numbers together, and all the variables

-4x^2+8x+(2x+1)^2+4=0

We move all terms containing x to the left, all other terms to the right

-4x^2+8x+(2x+1)^2=-4

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